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JEE Main 2007
Exam
JEE Main
Year
2007
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2007 · Physics · Motion in One Dimension

The velocity of a particle is v=v_0+gt+ft^2 . If its position is...

The velocity of a particle is v=v0+gt+ft2\mathrm{v}=\mathrm{v}_0+\mathrm{gt}+\mathrm{ft}^2. If its position is x=0\mathrm{x}=0 at t=0\mathrm{t}=0, then its displacement after unit time (t=1)(t=1) is

Options

  1. Av0+2g+3f\mathrm{v_0+2 g+3 f}
  2. Bv0+g/2+f/3\mathrm{v_0+g / 2+f / 3}
  3. Cv0+g+f\mathrm{v_0+g+f}
  4. Dv0+g/2+f\mathrm{v_0+g / 2+f}

Correct answer

B. v0+g/2+f/3\mathrm{v_0+g / 2+f / 3}

Step-by-step solution

∫0xdx=∫01(V0+gt+ft2)dt\mathrm{\int_0^x d x=\int_0^1\left(V_0+g t+\mathrm{ft}^2\right) d t} x=v0+g(12)+f(13)\mathrm{x=v_0+g\left(\frac{1}{2}\right)+f\left(\frac{1}{3}\right)}
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