JEE Main2007PhysicsMotion in One DimensionActual
The velocity of a particle is v = v ₀+ gt + ft ^2 . If its position is x =0 at t =0 , then its displacement after unit time (t=1) is
Options
- Av₀+2 g+3 f
- Bv₀+g / 2+f / 3
- Cv₀+g+f
- Dv₀+g / 2+f
Correct answer
B. v₀+g / 2+f / 3
Step-by-step solution
₀^x d x= ₀^1 (V₀+g t+ ft ^2 ) d t x=v₀+g ( 1 2 )+f ( 1 3 )