A body falling from rest under gravity passes a certain point P . It was at a distance of 400 ~m from P, 4 ~s prior to passing through P . If g=10 ~m / s ^2 , then the height above the point P from where the body began to fall is

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Correct answer: A. 720 m

We have h= 1 2 g t^2 ^2 and h+400= 1 2 g(t+4)^2 . Subtracting we get 400=8 ~g +4 gt aligned & t =8 sec & h = 1 2 10 64=320 ~m & Desired height =320+400=720 ~m . aligned

A body falling from rest under gravity passes a certain point P . It was at a distance of 400 ~m from P, 4 ~s prior to passing through P . If g=10 ~m / s ^2 , then the height above the point P from where the body began to fall is

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