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JEE Main2005PhysicsMotion in One DimensionActual

A car starting from rest accelerates at the rate f through a distance S , then continues at constant speed for time t and then decelerates at the rate f / 2 to come to rest. If the total distance traversed is 15 ~S , then

Options

  1. AS=f t
  2. BS =1 / 6 ft ^2
  3. CS =1 / 2 ft ^2
  4. DNone of these

Correct answer

D. None of these

Step-by-step solution

aligned & S = ft ₁^2 2 & v ₀= 2 Sf aligned During retardation S₂=2 S During constant velocity aligned & 15 ~S -3 ~S =12 ~S = v ₀ t & S = ft ^2 72 aligned

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