If a body looses half of its velocity on penetrating 3 cm in a wooden block, then how much will it penetrate more before coming to rest?

Step-by-step solution

Let the initial velocity of the body be v. Hence the final velocity = v/2 Applying v^2=u^2-2 a s ( v 2 )^2=v^2-2 a 3 a=v^2 / 8 In IInd case when the body comes to rest, final velocity = 0, initial velocity = v/2 Again, (0)^2= ( v 2 )^2-2 v^2 8 s ; or s=1 ~cm So the extra penetration will be 1 ~cm