JEE Main20253 Apr 2025Evening ShiftPhysicsMotion in Two DimensionsActual
A particle is projected with velocity u so that its horizontal range is three times the maximum height attained by it. The horizontal range of the projectile is given as n u^2 25 g , where value of n is : (Given ' g ' is the acceleration due to gravity).
Options
- A6
- B18
- C12
- D24
Correct answer
D. 24
Step-by-step solution
aligned & Range =3 H _ & u ^2 2 ~g = 3 u ^2 ^2 2 ~g aligned 2 = 3 2 ^2 = 4 3 =53^ R = u ^2 (2 3 5 4 5 ) g 24 u ^2 25 ~g