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JEE Main 20245 AprilEvening Shift

Exam: JEE Main
Year: 2024
Date: 5 April
Shift: Evening Shift
Subject: Physics
Chapter: Motion in Two Dimensions

JEE Main 2024 · 5 April · Evening Shift · Physics · Motion in Two Dimensions

The maximum height reached by a projectile is 64 ~m . If the...

The maximum height reached by a projectile is

64 \mathrm{~m}

. If the initial velocity is halved, the new maximum height of the projectile is _____

\mathrm{m}

.

Correct answer

0

Step-by-step solution

\begin{aligned} & \mathrm{H}_{\max }=\frac{\mathrm{u}^2 \sin ^2 \theta}{2 \mathrm{ g}} \\ & \frac{\mathrm{H}_{1 \text{ max }}}{\mathrm{H}_{2 \max }}=\frac{\mathrm{u}_1^2}{\mathrm{u}_2^2} \\ & \frac{64}{\mathrm{H}_{2 \max }}=\frac{\mathrm{u}^2}{(\mathrm{u} / 2)^2} \\ & \mathrm{H}_{2 \max }=16 \mathrm{ m}\end{aligned}

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