The range of the projectile projected at an angle of 15 ∘ with horizontal is 50 m . If the projectile is projected with same velocity at an angle of 45 ∘ with horizontal, then its range will be

Step-by-step solution

The data given is θ 1 = 15 ° θ 2 = 45 ° R 1 = 50   m The formula for range of a projectile is given by R = u 2   sin 2 θ g       . . . ( i ) Substituting the values in equation (i) R 1 = u 2 sin 2 θ 1 g ⇒ 50 = u 2 sin 30 ° g ⇒ u 2 g = 100 Let the new range be R 2 . The magnitude of the range is R 2 = u 2 sin 2 θ 2 g ⇒ R 2 = u 2 g sin 90 ° ⇒ R 2 = 100   m