An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at x = + 2m , its velocity is - 4 ^ j m s ^ - 1 . The object’s velocity ( v ) and

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An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at x = + 2m , its velocity is - 4 ^ j m s ^ - 1 . The object&rsquo;s velocity ( v ) and

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Correct answer: B. v = 4 ^ j m s ^ - 1 , a = 8 ^ i m s ^ - 2

An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the

As the speed is constant, only centripetal acceleration will act(towards the centre of the circular path), ${a}_{c} = \dfrac{{v}^{2}}{r} = \dfrac{{4}^{2}}{2} = 8m{s}^{- 2}$ towards the centre which at the given time will be towards right, hence $\overset{\to}{a}c = 8\overset{^}{i}m{s}^{- 2}$ . Velocity of the particle at this instant will in upward direction and hence $\overset{\to}{v} = 4\overset{^}{j}m{s}^{- 1}$ .

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