Two objects are projected with same velocity u however at different angles α and β with the horizontal. If α + β = 90 ° , the ratio of horizontal range of the first object to the 2 nd object will be :

Step-by-step solution

Given: α + β = 90 ° Range of the first projectile: R 1 = u 2 sin 2 α g Range of the second projectile: R 2 = u 2 sin 2 β g = u 2 sin ( 180 ° - 2 α ) g = u 2 sin 2 α g As we can see, both are equal. R 1 = R 2 Therefore, R 1 : R 2 = 1 : 1