A ball is projected with kinetic energy E , at an angle of 60 ° to...

A ball is projected with kinetic energy

E

, at an angle of

60 °

to the horizontal. The kinetic energy of this ball at the highest point of its flight will become : A ball is projected with kinetic energy E , at an angle of 60 ° to the horizontal. The kinetic energy of this ball at

A ball is projected with kinetic energy E , at an angle of 60 ° to the horizontal. The kinetic energy of this ball at

Options

AZero
B $\dfrac{E}{2}$
C $\dfrac{E}{4}$
D $E$

Correct answer

C. $\dfrac{E}{4}$

Step-by-step solution

$E = \dfrac{1}{2}m{u}^{2}$
At the Highest point, velocity is equal to the horizontal component of the velocity of projection. Therefore,
$v = ucos60 ° = \dfrac{u}{2}$
$∴$ Kinetic energy at the topmost point $= \dfrac{1}{2}m{\left(\dfrac{u}{2}\right)}^{2} = \dfrac{E}{4}$

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