At time t = 0 a particle starts travelling from a height 7 z ^ cm in a plane keeping z coordinate constant. At any instant of time, it's position along the x and y directions are defined as 3 t and 5 t 3 respectively. At t = 1 s acceleration of the particle will be

Step-by-step solution

The position vector of the particle can be written as, r → = 3 t i ^ + 5 t 3 j ^ + 7 k ^ The velocity of the particle will be, v → = d r → d t = 3 i ^ + 15 t 2 j ^ Now the acceleration of the particle will be, a → = d v → d t = d 2 r → d t 2 = 30 t j ^ At t = 1   s ⇒ d 2 r d t 2 = 30 j ^