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JEE Main202225 Jul 2022Evening ShiftPhysicsMotion in Two DimensionsActual

A ball is projected from the ground with a speed 15 m s - 1 at an angle θ with horizontal so that its range and maximum height are equal, then tan θ will be equal to

Options

  1. A1 4
  2. B1 2
  3. C2
  4. D4

Correct answer

D. 4

Step-by-step solution

The range and the maximum height of the projectile are given as below, R = u 2 sin 2 θ g = 2 u 2 sin θ cos θ g H = u 2 sin 2 θ 2 g Therefore, As H = R ⇒ tan θ = 4

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