A butterfly is flying with a velocity 4 2 m s - 1 in north-east direction. Wind is slowly blowing at 1 m s - 1 from north to south. The resultant displacement of the butterfly in 3 seconds is:

Step-by-step solution

V → BW = 4 2 cos 4 5 i ^ + 4 2 sin 4 5 j ^ = 4 i ^ + 4 j ^ V → w = - j ^ V → B = V → BW + V → w = 4 i ^ + 3 j ^ S → B = V → B × t = ( 4 i ^ + 3 j ^ ) × 3 = 12 i ^ + 9 j ^ S → B = ( 12 ) 2 + ( 9 ) 2 = 15   m