If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately : (Take : g = 10 ms - 2 , the radius of earth, R = 6400 × 10 3 m , Take π = 3 . 14 )

Step-by-step solution

For objects to float, m g = m ω 2 R ω = angular velocity of the earth. R = Radius of earth ω = g R       . . . 1 Duration of day = T T = 2 π ω       . . . 2 ⇒ T = 2 π R g = 2 π 6400 × 10 3 10 ⇒ T 60 = 83 . 775 minutes ≃ 84 minutes