If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately :
(Take : $g = 10{ms}^{- 2}$ , the radius of earth, $R = 6400 \times {10}^{3}m$ , Take $\pi = 3 . 14$ )

Question

If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately :
(Take :

g = 10{ms}^{- 2}

, the radius of earth,

R = 6400 \times {10}^{3}m

, Take

\pi = 3 . 14

)

Quantrex Academy · Accepted Answer

Correct answer: D. 84 minutes

For objects to float, mg = m ω ^ 2 R ω = angular velocity of the earth. R = Radius of earth ω = (g)/(R) . . . (1) Duration of day = T T = (2π)/(ω) . . . (2) ⇒ T = 2π (R)/(g) = 2π 6400 × 10 ^ 3 10 ⇒ (T)/(60) = 83 . 775 minutes ≃ 84 minutes

If the angular velocity of earth's spin is increased such that the...

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