A clock has a continuously moving second's hand of 0 . 1m length....

A clock has a continuously moving second's hand of $0 . 1m$ length. The average acceleration of the tip of the hand (in units of ${ms}^{- 2}$ ]) is of the order of :

Options

A ${10}^{- 3}$
B ${10}^{- 4}$
C ${10}^{- 2}$
D ${10}^{- 1}$

Correct answer

A. ${10}^{- 3}$

Step-by-step solution

The instantaneous acceleration of tip is given by

$ac = {\omega}^{2}R = {\left(\dfrac{2\pi}{60}\right)}^{2} \times 0 . 1 = \dfrac{1}{900} \approx {10}^{- 3}$

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