JEE Main 201912 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 12 April
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Motion in Two Dimensions
JEE Main 2019 · 12 April · Morning Shift · Physics · Motion in Two Dimensions
The trajectory of a projectile near the surface of the earth is...
The trajectory of a projectile near the surface of the earth is given as If it were launched at an angle with speed then \left(g = 10{ms}^{- 2}\right):
Options
- A{\theta}_{0} = \cos^{- 1} and
- B{\theta}_{0} = \cos^{- 1} and
- C{\theta}_{0} = \sin^{- 1} and
- D{\theta}_{0} = \sin^{- 1} and
Correct answer
A. {\theta}_{0} = \cos^{- 1} and
Step-by-step solution
Comparing above equation with general equation of trajectory of projectile
or
or
And R = 2/9
After substituting the value for g and \sin 2θ. We get m/s