Two particles A, B are moving on two concentric circles of radii R _ 1 and R _ 2 with equal angular speed ω . At t = 0, their positions and direction of motion are shown in the figure: The relative velocity → V _ A - →

Correct answer: D. ω ( R _ 2 - R _ 1 ) ^ i t = (π)/(2ω) → V _ A = ω R _ 1 (- ^ i ) → V _ B = ω R _ 2 (- ^ i ) → V _ A - → V _ B = ω( R _ 2 - R _ 1 ) ^ i

JEE Main 201912 JanuaryEvening Shift

Exam: JEE Main
Year: 2019
Date: 12 January
Shift: Evening Shift
Subject: Physics
Chapter: Motion in Two Dimensions

JEE Main 2019 · 12 January · Evening Shift · Physics · Motion in Two Dimensions

Two particles A, B are moving on two concentric circles of radii R...

Two particles $A, B$ are moving on two concentric circles of radii ${R}_{1}$ and ${R}_{2}$ with equal angular speed $\omega .$ At $t = 0,$ their positions and direction of motion are shown in the figure:

Two particles A, B are moving on two concentric circles of radii R _ 1 and R _ 2 with equal angular speed ω . At t = 0,

The relative velocity $\overset{\to}{{V}_{A}} - \overset{\to}{{V}_{B}}$ at $t = \dfrac{\pi}{2\omega}$ is given by:

Options

A- \omega $\left({R}_{1} + {R}_{2}\right)\overset{^}{i}$
B\omega $\left({R}_{1} + {R}_{2}\right)\overset{^}{i}$
C\omega $\left({R}_{1} - {R}_{2}\right)\overset{^}{i}$
D\omega $\left({R}_{2} - {R}_{1}\right)\overset{^}{i}$

Correct answer

D. \omega $\left({R}_{2} - {R}_{1}\right)\overset{^}{i}$

Step-by-step solution

$t = \dfrac{\pi}{2\omega}$

Two particles A, B are moving on two concentric circles of radii R _ 1 and R _ 2 with equal angular speed ω . At t = 0,

${\overset{\to}{V}}_{A} = \omega{R}_{1}\left(- \overset{^}{i}\right)$

${\overset{\to}{V}}_{B} = \omega{R}_{2}\left(- \overset{^}{i}\right)$

$\overset{\to}{{V}_{A}} - \overset{\to}{{V}_{B}} = \omega\left({R}_{2} - {R}_{1}\right)\overset{^}{i}$

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