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JEE Main 20137 April

Exam: JEE Main
Year: 2013
Date: 7 April
Subject: Physics
Chapter: Motion in Two Dimensions

JEE Main 2013 · 7 April · Physics · Motion in Two Dimensions

A projectile is given an initial velocity of ( ^ i + 2 ^ j )m s ^ -...

A projectile is given an initial velocity of

\left(\overset{^}{i} + 2\overset{^}{j}\right)m{s}^{- 1}

, where

\overset{^}{\text{i}}

is along the ground and

\overset{^}{\text{j}}

is along the vertical upward. If

g = 10 m {s}^{- 2}

, the equation of its trajectory is :

Options

A $4y = 2x - 5{x}^{2}$
B $4y = 2x - 25{x}^{2}$
C $y = x - 5{x}^{2}$
D $y = 2x - 5{x}^{2}$

Correct answer

D. $y = 2x - 5{x}^{2}$

Step-by-step solution

\overset{\to}{\text{v}} = \overset{^}{\text{i}} + 2 \overset{^}{\text{j}}

<br /><br />

\to \text{x} = \text{t}

..... (i)<br /><br />

\text{y} = 2 \text{t} - \dfrac{1}{2}

\left(1 0 {\text{t}}^{2}\right)

..... (ii)

From (i) and (ii)

\text{y} = 2 \text{x} - 5 {\text{x}}^{2}

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