JEE Main2013PhysicsMotion in Two DimensionsActual
A projectile is given an initial velocity of i ^ + 2 j ^ m s - 1 , where i ^ is along the ground and j ^ is along the vertical upward. If g = 10 m s - 2 , the equation of its trajectory is :
Options
- A4 y = 2 x - 5 x 2
- B4 y = 2 x - 25 x 2
- Cy = x - 5 x 2
- Dy = 2 x - 5 x 2
Correct answer
D. y = 2 x - 5 x 2
Step-by-step solution
v → = i ^ + 2 j ^ ⇒ x = t ..... (i) y = 2 t - 1 2 1 0 t 2 ..... (ii) From (i) and (ii) y = 2 x - 5 x 2