A boy can throw a stone up to a maximum height of 10 ~m . The maximum horizontal distance that the boy can throw the same stone up to will be

Step-by-step solution

maximum vertical height = u^2 2 g =10 ~m Horizontal range of a projectile = u^2 2 g Range is maximum when =45^ Maximum horizontal range = u ^2 ~g Hence maximum horizontal distance =20 ~m .