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JEE Main 2011
Exam
JEE Main
Year
2011
Subject
Physics
Chapter
Motion in Two Dimensions

JEE Main 2011 · Physics · Motion in Two Dimensions

A water fountain on the ground sprinkles water all around it. If...

A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is v\mathrm{v}, the total area around the fountain that gets wet is :

Options

  1. Aπv4g2\pi \frac{v^4}{g^2}
  2. Bπ2v4g2\frac{\pi}{2} \frac{v^4}{g^2}
  3. Cπv2g2\pi \frac{v^2}{g^2}
  4. Dπv4g\pi \frac{v^4}{g}

Correct answer

A. πv4g2\pi \frac{v^4}{g^2}

Step-by-step solution

Max. range =u2 g=\frac{u^2}{\mathrm{~g}} i.e., v2 g\frac{v^2}{\mathrm{~g}} (radius of circle) \text{ Area occupied }=\pi\left(\frac{\mathrm{v}^2}{\mathrm{~g}}\right)^2=πv4 g2\frac{\pi \mathrm{v}^4}{\mathrm{~g}^2}
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