JEE Main2011PhysicsMotion in Two DimensionsActual
A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is v , the total area around the fountain that gets wet is :
Options
- Av^4 g^2
- B2 v^4 g^2
- Cv^2 g^2
- Dv^4 g
Correct answer
A. v^4 g^2
Step-by-step solution
Max. range = u^2 ~g i.e., v^2 ~g (radius of circle) Area occupied = ( v ^2 ~g )^2= v ^4 ~g ^2