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JEE Main2004PhysicsMotion in Two DimensionsActual

If t₁ and t₂ are the times of flight of two particles having the same initial velocity u and range R on the horizontal, then t ₁^2+ t ₂^2 is equal to

Options

  1. Au^2 g
  2. B4 u^2 g^2
  3. Cu^2 2 g
  4. D1

Correct answer

B. 4 u^2 g^2

Step-by-step solution

t ₁= 2 u g , t ₂= 2 u g where + =90^ t ₁^2+ t ₂^2= 4 u ^2 ~g ^2

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