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An atom ₃⁸ X is bombarded by shower of fundamental particles and in 10 s this atom absorbed 10 electrons, 10 protons and 9 neutrons. The percentage growth in the surface area of the nucleons is recorded by:

Options

  1. A250 %
  2. B150 %
  3. C900 %
  4. D125 %

Correct answer

D. 125 %

Step-by-step solution

Surface area x A^ 2/3 X_i = 8^ 2/3 K = 4K X_f = (8 + 10 + 9)^ 2/3 K = 9K % increase in surface area of nucleus x_i = 9K - 4K 4K 100 = 125 %

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