An atom _ 3 ^ 8 X is bombarded by shower of fundamental particles...

An atom

{ }_{3}^{8} X

is bombarded by shower of fundamental particles and in 10 s this atom absorbed 10 electrons, 10 protons and 9 neutrons. The percentage growth in the surface area of the nucleons is recorded by:

Options

A $250 \%$
B $150 \%$
C $900 \%$
D $125 \%$

Correct answer

D. $125 \%$

Step-by-step solution

Surface area

x \propto A^{2/3}

X_i = 8^{2/3} K = 4K

X_f = (8 + 10 + 9)^{2/3} K = 9K

% increase in surface area of nucleus

x_i = \dfrac{9K - 4K}{4K} \times 100 = 125\%

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