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JEE Main 202624 JanuaryEvening Shift

Exam: JEE Main
Year: 2026
Date: 24 January
Shift: Evening Shift
Subject: Physics
Chapter: Nuclear Physics

JEE Main 2026 · 24 January · Evening Shift · Physics · Nuclear Physics

The binding energy for the following nuclear reactions are...

The binding energy for the following nuclear reactions are expressed in MeV.

{ }_{2} \mathrm{He}^{3}+{ }_{0} \mathrm{n}^{1} \rightarrow{ }_{2} \mathrm{He}^{4}+20 \mathrm{MeV}

{ }_{2} \mathrm{He}^{4}+{ }_{0} \mathrm{n}^{1} \rightarrow{ }_{2} \mathrm{He}^{5}-0.9 \mathrm{MeV}

If

\mathrm{X}_{3}, \mathrm{X}_{4}, \mathrm{X}_{5}

denote the stability of

{ }_{2} \mathrm{He}^{3},{ }_{2} \mathrm{He}^{4}

and

{ }_{2} \mathrm{He}^{5}

, respectively, then the correct order is :

Options

A $\mathrm{X}_{4}<\mathrm{X}_{5}<\mathrm{X}_{3}$
B $\mathrm{X}_{4}>\mathrm{X}_{5}>\mathrm{X}_{3}$
C $\mathrm{X}_{4}>\mathrm{X}_{5}<\mathrm{X}_{3}$
D $\mathrm{X}_{4}=\mathrm{X}_{5}=\mathrm{X}_{3}$

Correct answer

B. $\mathrm{X}_{4}>\mathrm{X}_{5}>\mathrm{X}_{3}$

Step-by-step solution

BE_{He^4} - BE_{He^3} = 20 MeV

...(1)

BE_{He^5} - BE_{He^4} = -0.9 MeV

...(2)
From eq (1) & (2)

BE_{He^4} > BE_{He^5} > BE_{He^3}

X_4 > X_5 > X_3

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