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JEE Main 20248 AprilEvening Shift
Exam
JEE Main
Year
2024
Date
8 April
Shift
Evening Shift
Subject
Physics
Chapter
Nuclear Physics

JEE Main 2024 · 8 April · Evening Shift · Physics · Nuclear Physics

In a hypothetical fission reaction _ 92 X^ 236 arrow _ 56 Y^ 141 +...

In a hypothetical fission reaction 92X236→56Y141+36Z92+3R{ }_{92} X^{236} \rightarrow{ }_{56} Y^{141}+{ }_{36} Z^{92}+3 R The identity of emitted particles ( R)\mathrm{R}) is :

Options

  1. AElectron
  2. BNeutron
  3. Cγ\gamma-radiations
  4. DProton

Correct answer

B. Neutron

Step-by-step solution

Z in LHS =92Z in RHS=56+36=92A in LHS=236A in RHS=141+92=233\begin{aligned} & \mathrm{Z} \text{ in LHS }=92 \\ & \mathrm{Z} \text{ in } \mathrm{RHS}=56+36=92 \\ & \mathrm{ A} \text{ in } \mathrm{LHS}=236 \\ & \mathrm{ A} \text{ in } \mathrm{RHS}=141+92=233 \end{aligned}So 3 neutrons are released.
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