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JEE Main 20248 AprilMorning Shift

Exam: JEE Main
Year: 2024
Date: 8 April
Shift: Morning Shift
Subject: Physics
Chapter: Nuclear Physics

JEE Main 2024 · 8 April · Morning Shift · Physics · Nuclear Physics

Binding energy of a certain nucleus is 18 × 10^8 ~J . How much is...

Binding energy of a certain nucleus is

18 \times 10^8 \mathrm{~J}

. How much is the difference between total mass of all the nucleons and nuclear mass of the given nucleus:

Options

A $10 \mu \mathrm{g}$
B $20 \mu \mathrm{g}$
C $0.2 \mu \mathrm{g}$
D $2 \mu \mathrm{g}$

Correct answer

B. $20 \mu \mathrm{g}$

Step-by-step solution

\begin{aligned} & \Delta \mathrm{mc}^2=18 \times 10^8 \\ & \Delta \mathrm{m} \times 9 \times 10^{16}=18 \times 10^8 \\ & \Delta \mathrm{m}=2 \times 10^{-8} \mathrm{~kg}=20 \mu \mathrm{g}\end{aligned}

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