The disintegration energy Q for the nuclear fission of ²³⁵ U ¹⁴⁰ Ce + ⁹⁴ Zr +n is ______ MeV . Given atomic masses of ²³⁵ U : 235.0439 u ; ¹⁴⁰ Ce : 139.9054 u , ⁹⁴ Zr : 93.9063 u ; n: 1.0086 u , Value of c^2=931 MeV / u

Step-by-step solution

²³⁵ U ¹⁴⁰ Ce + ⁹⁴ Zr + n Disintegration energy aligned Q & = ( m _ R - m _ p ) c ^2 ~m _ R & =235.0439 u m _ p & =139.9054 u +93.9063 u +1.0086 u & =234.8203 u Q & =(235.0439 u -234.8203 u ) c ^2 & =0.2236 c ^2 & =0.2236 931 Q & =208.1716 aligned