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JEE Main20245 Apr 2024Morning ShiftPhysicsNuclear PhysicsActual

If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is _____ 10⁻² MeV . (Given 1 u =931 MeV / c ^2 , atomic mass of helium =4.002603 u )

Correct answer

0

Step-by-step solution

Reaction : aligned & 3 ₂^4 He ₆¹² C + rays & Mass defect = m = (3 ~m _ He - m _ C ) & =(3 4.002603-12)=0.007809 u aligned Energy released =931 m MeV =7.27 MeV =727 10⁻² MeV

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