The atomic mass of C 12 6 is 12 . 000000 u and that of C 13 6 is 13 . 003354 u . The required energy to remove a neutron from C 13 6 , if mass of neutron is 1 . 008665 u , will be:

Step-by-step solution

Given the nuclear reaction is C 13 6 + Energy → C 12 6 + n 1 0 The mass defect for the above reaction can be calculated as follows: Δ m = ( 12 . 000000 + 1 . 008665 ) - 13 . 003354 u = - 0 . 00531 u Hence, the energy required is given by E = 0 . 00531 × 931 . 5 MeV = 4 . 95 MeV