JEE Main202427 Jan 2024Morning ShiftPhysicsNuclear PhysicsActual
In a nuclear fission process, a high mass nuclide ( A ≈ 236 ) with binding energy 7 . 6 MeV / Nucleon dissociated into two middle mass nuclides ( A ≈ 118 ) , having binding energy of 8 . 6 MeV / Nucleon. The energy released in the process would be _______ MeV .
Correct answer
0
Step-by-step solution
The formula to calculate the energy released in the given process can be written as Q = B E Product - B E Reactant . . . 1 From equation (1), it follows that Q = 2 ( 118 ) ( 8 . 6 ) - 236 ( 7 . 6 ) MeV = 236 MeV