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JEE Main 202427 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
27 January
Shift
Morning Shift
Subject
Physics
Chapter
Nuclear Physics

JEE Main 2024 · 27 January · Morning Shift · Physics · Nuclear Physics

In a nuclear fission process, a high mass nuclide ( A 236 ) with...

In a nuclear fission process, a high mass nuclide (A≈236)( A \approx 236 ) with binding energy 7.6MeV/7 . 6MeV /Nucleon dissociated into two middle mass nuclides (A≈118)( A \approx 118 ), having binding energy of 8.6MeV/8 . 6MeV /Nucleon. The energy released in the process would be _______ MeVMeV.

Correct answer

0

Step-by-step solution

The formula to calculate the energy released in the given process can be written as

Q=BEProduct−BEReactant...(1)Q = B{E}_{\text{Product}} - B{E}_{\text{Reactant}} . . . \left(1\right)

From equation (1), it follows that

{Q=2(118)(8.6)−236(7.6)MeV=236MeV\begin{cases}Q & = & 2 ( 118 ) ( 8 . 6 ) - 236 ( 7 . 6 ) MeV \\ & = & 236MeV\end{cases}

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