JEE Main202331 Jan 2023Evening ShiftPhysicsNuclear PhysicsActual
If the binding energy of ground state electron in a hydrogen atom is 13 . 6 eV , then, the energy required to remove the electron from the second excited state of Li 2 + will be: x × 10 - 1 eV . The value of x is _____.
Correct answer
0
Step-by-step solution
Given: Binding energy, E H = E 0 = 13 . 6   eV . Now for hydrogen like atom, we can write E Li 2 + = E 0 Z 2 n 2 = 13 . 6 × 9 9 = 13 . 6   eV = 136 × 10 - 1   eV Therefore, x = 136 .