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JEE Main 202324 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
24 January
Shift
Morning Shift
Subject
Physics
Chapter
Nuclear Physics

JEE Main 2023 · 24 January · Morning Shift · Physics · Nuclear Physics

Assume that protons and neutrons have equal masses. Mass of a...

Assume that protons and neutrons have equal masses. Mass of a nucleon is 1.6×10−27kg1 . 6 \times {10}^{- 27}kg and radius of nucleus is 1.5×10−15A13m1 . 5 \times {10}^{- 15}A\dfrac{1}{3}m. The approximate ratio of the nuclear density and water density is n×1013n \times {10}^{13}. The value of nn is _____.

Correct answer

0

Step-by-step solution

As we know, density of nuclei=mass of nucleivolume of nuclei\text{density of nuclei} = \dfrac{\text{mass of nuclei}}{\text{volume of nuclei}}

⇒ρ=1.6×10−27A43π(1.5×10−15)3A⇒ ρ = \dfrac{1 . 6 \times {10}^{- 27}A}{\dfrac{4}{3}\pi{\left(1 . 5 \times {10}^{- 15}\right)}^{3}A}

=1.6×10−2714.14×10−45=0.113×1018kgm−3= \dfrac{1 . 6 \times {10}^{- 27}}{14 . 14 \times {10}^{- 45}} = 0 . 113 \times {10}^{18}kg{m}^{- 3}

We also know that, density of water is ρw=103kgm−3{ρ}_{w} = {10}^{3}kg{m}^{- 3}.

Hence,
ρρw=11.31×1013\dfrac{ρ}{{ρ}_{w}} = 11 . 31 \times {10}^{13}.

Therefore, n≈11n \approx 11

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