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Consider the following radioactive decay process: A 84 218 ⟶ α A 1 ⟶ β - A 2 ⟶ γ A 3 ⟶ α A 4 ⟶ β + A 5 ⟶ γ A 6 The mass number and the atomic number of A 6 are given by:

Options

  1. A210 and 82
  2. B210 and 84
  3. C210 and 80
  4. D211 and 80

Correct answer

C. 210 and 80

Step-by-step solution

When an alpha particle is emitted from nucleus the nucleus loses two proton and two neutrons. This means the atomic mass number decreases by 4 and the atomic number decreases by 2. In beta decays, the mass number of the atoms remains the same, but the atomic number changes: the atomic number increases in the negative beta decay and decreases in the positive beta decay by 1 , respectively. In gamma decay, mass number and atomic number remains unchanged. Step by step variation is given below:   84 218 A ⟶

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