Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 202228 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
28 June
Shift
Evening Shift
Subject
Physics
Chapter
Nuclear Physics

JEE Main 2022 · 28 June · Evening Shift · Physics · Nuclear Physics

Following statements related to radioactivity are given below : (A)...

Following statements related to radioactivity are given below :
(A) Radioactivity is a random and spontaneous process and is dependent on physical and chemical conditions.
(B) The number of undecayed nuclei in the radioactive sample decays exponentially with time.
(C) Slope of the graph of log⁡e\log_{e} (no. of undecayed nuclei) vs. time represents the reciprocal of mean life time \left(τ\right).<br/>(D)Productofdecayconstant(λ).<br />(D) Product of decay constant \left(\lambda\right) and half-life time (T12)\left(T\dfrac{1}{2}\right) is not constant.

Choose the most appropriate answer from the options given below:

Options

  1. A(A) and (B) only
  2. B(B) and (D) only
  3. C(B) and (C) only
  4. D(C) and (D) only

Correct answer

C. (B) and (C) only

Step-by-step solution

Radioactive decay is a random and spontaneous process, it depends on unbalancing of nucleus. This process is dependent on the law of conservation of charge.

We know that, N=N0e−\lambdat...(1),Where,N = {N}_{0}{e}^{- \lambdat} . . . \left(1\right), Where,N=numberofdecayednucleiinthesampleattime=number of decayed nuclei in the sample at timet and {N}_{0} =initialnumberofnuclei.</p><p>Hence,totalnumberofundecayednucleiinitial number of nuclei.</p><p>Hence, total number of undecayed nuclei{N}_{0} - N</p><p>Thus,</p><p>Thus,{N}_{0} - N = {N}_{0}\left(1 - {e}^{- \lambdat}\right)</p><p>Thisshowsthatthetotalnumberofundecayednucleidecaysexponentiallywithtime.</p><p>Takinglogbothsidesofequation</p><p>This shows that the total number of undecayed nuclei decays exponentially with time. </p><p>Taking log both sides of equation\left(1\right)</p><p></p><p>lnN = - \lambdat + ln{N}_{0}</p><p>So,slope</p><p>So, slope= - \lambda(reciprocalofmeanlifetime)</p><p>Halflifetime(reciprocal of mean life time)</p><p>Half life timeT\dfrac{1}{2} = \dfrac{\ln 2}{\lambda}</p><p>Then,</p><p>Then,\lambda \times T\dfrac{1}{2} = \ln 2 = constant

Hence, (B) and (C) are correct only.

Practice Nuclear Physics on Quantrex Academy →

More from Nuclear Physics

A nuclear reactor starts producing a radioactive nuclide X from t = 0 , at a constant… JEE Advanced 2026Two radioactive substances A and B of mass numbers 200 and 212 respectively, shows… JEE Main 2026The energy released if hydrogen atoms are combined to form ^ 4 _ 2 He is __________ MeV.… JEE Main 2026The energy released when (7)/(17.13) kg of ^ 7 _ 3 Li is converted into ^ 4 _ 2 He by… JEE Main 2026Assuming the experimental mass of ^ 12 _ 6 C as 12 u , the mass defect of ^ 12 _ 6 C atom… JEE Main 2026Two nuclei of mass number 3 combine with another nucleus of mass number 4 to yield a… JEE Main 2026The binding energy per nucleon of ^ 209 _ 83 Bi is _______ MeV. [Take m(^ 209 _ 83 Bi) =… JEE Main 2026A nucleus has mass number α and radius R_ α . Another nucleus has mass number β and… JEE Main 2026 Full Nuclear Physics list All JEE Main PYQs