A nucleus with mass number 184 initially at rest emits an α - particle. If the Q value of the reaction is 5 . 5 MeV , calculate the kinetic energy of the α - particle.

Step-by-step solution

1 2 4   m v 2 + 1 2 180   m 4 v 180 2 = 5 . 5   MeV ⇒    1 2 4   mv 2 1 + 45 4 180 2 = 5 . 5   MeV ⇒    K . E . α = 5 . 5 1 + 45 · 4 180 2   MeV = 5 . 38   MeV