For a certain radioactive process, the graph between lnR and t (...

For a certain radioactive process, the graph between $lnR$ and $t ( sec )$ is obtained as shown in the figure. Then the value of half life for the unknown radioactive material is approximately:

For a certain radioactive process, the graph between lnR and t ( sec ) is obtained as shown in the figure. Then the

Options

A $9 . 15sec$
B $6 . 93sec$
C $2 . 62sec$
D $4 . 62sec$

Correct answer

D. $4 . 62sec$

Step-by-step solution

$R = {R}_{0}{e}^{- \lambdat}$

$ℓnR = ℓn{R}_{0} - \lambdat$

$- \lambda$ is slope of straight line

$\lambda = \dfrac{3}{20}$

${t}_{1/2} = \dfrac{ℓn2}{\lambda} = 4 . 62$

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