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Find the Binding energy per nucleon for Sn 50 120 . Mass of proton m p = 1 . 00783 U , mass of neutron m n = 1 . 00867 U and mass of tin nucleus m sn = 119 . 902199 U . (take 1 U = 931 M e V )

Options

  1. A7 .5 M e V
  2. B9 . 0 M e V
  3. C 8. 0 M e V
  4. D8 .5 M e V

Correct answer

D. 8 .5 M e V

Step-by-step solution

Binding energy = ( ΔM ) C 2 = ( AM ) 931 put the value of ∆ M BE = 8 . 5 MeV

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