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JEE Main 20204 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
4 September
Shift
Evening Shift
Subject
Physics
Chapter
Nuclear Physics

JEE Main 2020 · 4 September · Evening Shift · Physics · Nuclear Physics

Find the Binding energy per nucleon for Sn 50120 . Mass of proton m...

Find the Binding energy per nucleon for Sn50120Sn 50120. Mass of proton mp=1.00783U{m}_{p} = 1 . 00783U, mass of neutron mn=1.00867U{m}_{n} = 1 . 00867U and mass of tin nucleus msn=119.902199U{m}_{sn} = 119 . 902199U. (take 1U=931MeV1U = 931MeV)

Options

  1. A7.5MeV7 .5 MeV
  2. B9.0MeV9 . 0MeV
  3. C8.0MeV8. 0MeV
  4. D8.5MeV8 .5 MeV

Correct answer

D. 8.5MeV8 .5 MeV

Step-by-step solution

Binding energy =(ΔM)C2=(AM)931= ( \Delta M ) {C}^{2} = ( AM ) 931

put the value of ∆M∆ M

BE=8.5MeVBE = 8 . 5MeV

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