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JEE Main 20203 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
3 September
Shift
Evening Shift
Subject
Physics
Chapter
Nuclear Physics

JEE Main 2020 · 3 September · Evening Shift · Physics · Nuclear Physics

The radius R of a nucleus of mass number A can be estimated by the...

The radius RR of a nucleus of mass number AA can be estimated by the formula R=(1.3×10−15)A1/3mR = \left(1 . 3 \times {10}^{- 15}\right){A}^{1 / 3}m. It follows that the mass density of n nucleus is of the order of: \left({M}_{prot} ≅ {M}_{\text{neut}} ≃ 1 . 67 \times {10}^{- 27}kg\right)

Options

  1. A103kgm−3{10}^{3}kg{m}^{- 3}
  2. B1010kgm−3{10}^{10}kg{m}^{- 3}
  3. C1024kgm−3{10}^{24}kg{m}^{- 3}
  4. D1017kgm−3{10}^{17}kg{m}^{- 3}

Correct answer

D. 1017kgm−3{10}^{17}kg{m}^{- 3}

Step-by-step solution

ρnucleus = mass  volume =A(4/3)πr03A=34πr03=2.3×1017kg/\rho_{\text{nucleus }}=\frac{\text{ mass }}{\text{ volume }} =\frac{A}{(4 / 3) \pi r_0^3 \mathrm{ A}}=\frac{3}{4 \pi \mathrm{r}_0^3} =2.3 \times 10^{17} \mathrm{ kg} /m3\mathrm{m}^3
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