In a radioactive decay chain, the initial nucleus is 90 232 Th . At the end, there are 6 α -particles and 4 β -particles which are emitted. If the end nucleus is Z A X , A and Z are given by:

Step-by-step solution

As we know that in alpha decay mass number reduced from for and the atomic number reduced by two and in beta decay the mass number became unchange and atomic number increase from one Change in Z = 6 × 2 - 4 = 8 Change in A = 6 × 4 - 4 = 8 TH 90 232 → 6 α 4 β   P B 82 208