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JEE Main201910 Jan 2019Evening ShiftPhysicsNuclear PhysicsActual

Consider the nuclear fission, Ne 20 → 2 He 4 + C 12 . Given that the binding energy/nucleon of Ne 20 , He 4   and   C 12 are 8.03   MeV , 7.86 MeV , respectively. Identify the correct statement:

Options

  1. AEnergy of 12 . 4   MeV will be supplied.
  2. BEnergy of 9 . 72   MeV has to be supplied.
  3. CEnergy of 3 . 6   MeV will be released.
  4. D8 . 3   MeV energy will be released.

Correct answer

B. Energy of 9 . 72   MeV has to be supplied.

Step-by-step solution

Q = E f - E i = 12 × 7.86 + 4 × 7.07 + 4 × 7.07 - ( 20 × 8.03 ) Q = - 9.72   MeV

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