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JEE Main 20179 AprilOnline
Exam
JEE Main
Year
2017
Date
9 April
Mode
Online
Subject
Physics
Chapter
Nuclear Physics

JEE Main 2017 · 9 April · Online · Physics · Nuclear Physics

Imagine that a reactor converts all the given mass into energy and...

Imagine that a reactor converts all the given mass into energy and that it operates at a power level of 109Watt{10}^{9}Watt . The mass of the fuel consumed perhourperhour, in the reactor, will be:
(velocity of light, cc is 3×108ms−13 \times {10}^{8}m{s}^{- 1})

Options

  1. A6.6×10−5g6.6 \times {10}^{- 5}g
  2. B0.96g0.96g
  3. C4×10−2g4 \times {10}^{- 2}g
  4. D0.8g0.8g

Correct answer

C. 4×10−2g4 \times {10}^{- 2}g

Step-by-step solution

Power of reactor, P=E\Deltat=\Deltamc2\DeltatP = \dfrac{E}{\Deltat} = \dfrac{\Deltam{c}^{2}}{\Deltat}(From mass-energy equivalence equation)

Given in the problem power level =109Watt= {10}^{9}Watt .

∆m∆t=Pc2=109(3×108)2\dfrac{∆ m}{∆ t} = \dfrac{P}{{c}^{2}} = \dfrac{{10}^{9}}{{\left(3 \times {10}^{8}\right)}^{2}}

⇒∆m∆t=10−79kgs−1⇒ \dfrac{∆ m}{∆ t} = \dfrac{{10}^{- 7}}{9}kg{s}^{- 1}

The mass of fuel consumed perhourperhour=10−79×(1000g)(3600h−1)=4×10−2gh−1= \dfrac{{10}^{- 7}}{9} \times \left(1000g\right)\left(3600{h}^{- 1}\right) = 4 \times {10}^{- 2}g{h}^{- 1}.

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