Imagine that a reactor converts all the given mass into energy and that it operates at a power level of 10 9 Watt . The mass of the fuel consumed per hour , in the reactor, will be: (velocity of light, c is 3 × 10 8 m s - 1 )

Step-by-step solution

Power of reactor, P = E Δ t = Δ m c 2 Δ t (From mass-energy equivalence equation) Given in the problem power level = 10 9   Watt . ∆ m ∆ t = P c 2   = 10 9 3 × 10 8 2 ⇒   ∆ m ∆ t = 10 - 7 9   k g   s - 1   The mass of fuel consumed per   hour = 10 - 7 9 × 1000  g 3600   h - 1 = 4 × 10 - 2  g  h - 1 .