A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec. The time required by it to move from x = A to x = A 2 is _______ sec.

Step-by-step solution

The equation of simple harmonic motion for a particle starting from the extreme position x = A is given by: x = A ( t) We need to find the time t when the particle reaches x = A 2 . Substituting this value into the equation: A 2 = A ( t) ( t) = 1 2 t = 4 Since the angular frequency = 2 T , we have: 2 T t = 4 t = T 8 Given the time period T = 5 sec, the required time is: t = 5 8 sec Answer: 5/8