A ray of light passing through an equilateral prism is having velocity 2.12 10^8 m/s in the prism material, then the minimum angle of deviation is _________ degrees.

Step-by-step solution

Velocity of light in vacuum, c = 3 10^8 m/s Velocity of light in the prism, v = 2.12 10^8 m/s Refractive index of the prism material, = c v = 3 10^8 2.12 10^8 1.414 2 For an equilateral prism, the angle of the prism A = 60^ . Using the prism formula: = ( A + _m 2 ) ( A 2 ) 2 = ( 60^ + _m 2 ) (30^ ) 2 = (30^ + _m 2 ) 1 2 (30^ + _m 2 ) = 2 2 = 1 2 30^ + _m 2 = 45^ _m 2 = 15^ _m = 30^ Answer: 30