For a thin symmetric prism made of glass (refractive index 1.5 ), the ratio of incident angle and minimum deviation will be _______.

Step-by-step solution

For a thin prism, the angle of minimum deviation is given by _m = ( - 1)A . At the position of minimum deviation, the angle of incidence i and angle of emergence e are equal, and the angle of refraction is r = A 2 . Using Snell's law for small angles, i = r = ( A 2 ) . The ratio of the incident angle to the minimum deviation is: i _m = A 2 ( - 1)A = 2( - 1) Given = 1.5 , substituting the value: i _m = 1.5 2(1.5 - 1) = 1.5 2(0.5) = 1.5 1 = 3 2 Answer: 3 : 2