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A container contains a liquid with refractive index of 1.2 up to a height of 60 cm and another liquid having refractive index 1.6 is added to height H above first liquid. If viewed from above, the apparent shift in the position of bottom of container is 40 cm. The value of H is ______ cm. (Consider liquids are immisible)

Correct answer

0

Step-by-step solution

y= apparent depth of bottom y 1 = H 1.6 + 60 1.2 Shift =40 H+60-y=40 H +60- H 1.6 - 60 1.2 =40 6 16 H =30 H =80 ~cm

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