A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to 60^ . The refractive index of the prism material is 2 . The angle of incidence (in degrees) is ______.

Correct answer: 0 aligned & μ= ( A+ _ m 2 ) ( A 2 ) , since A=60^ m=30^ & _ m =2 i-A[ as i=e] & i=45^ aligned

JEE Main 20252 AprilEvening Shift

JEE Main 2025 · 2 April · Evening Shift · Physics · Ray Optics

A ray of light suffers minimum deviation when incident on a prism...

A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to

60^{\circ}

. The refractive index of the prism material is

\sqrt{2}

. The angle of incidence (in degrees) is ______.

\begin{aligned} & \mu=\frac{\sin \left(\frac{\mathrm{A}+\delta_{\mathrm{m}}}{2}\right)}{\sin \left(\frac{\mathrm{A}}{2}\right)}, \text{ since } \mathrm{A}=60^{\circ} \quad \therefore \delta \mathrm{m}=30^{\circ} \\ & \delta_{\mathrm{m}}=2 \mathrm{i}-\mathrm{A}[\text{ as } \mathrm{i}=\mathrm{e}] \\ & \Rightarrow \mathrm{i}=45^{\circ}\end{aligned}