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JEE Main 20252 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
2 April
Shift
Morning Shift
Subject
Physics
Chapter
Ray Optics

JEE Main 2025 · 2 April · Morning Shift · Physics · Ray Optics

A spherical surface separates two media of refractive indices 1 and...

A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an
A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object ' O ', is :
( C is the center of curvature of the spherical surface and RR is the radius of curvature)

Options

  1. A0.24 m right to the spherical surface
  2. B0.4 m left to the spherical surface
  3. C0.24 m left to the spherical surface
  4. D0.4 m right to the spherical surface

Correct answer

B. 0.4 m left to the spherical surface

Step-by-step solution

μ2v−μ1u=μ2−μ1R1.5v−1(−0.2)=1.5−10.41.5v=0.50.4−10.21.5v=−1.50.4v=−0.4 m\begin{aligned} & \frac{\mu_2}{\mathrm{v}}-\frac{\mu_1}{\mathrm{u}}=\frac{\mu_2-\mu_1}{\mathrm{R}} \\ & \frac{1.5}{\mathrm{v}}-\frac{1}{(-0.2)}=\frac{1.5-1}{0.4} \\ & \frac{1.5}{\mathrm{v}}=\frac{0.5}{0.4}-\frac{1}{0.2} \\ & \frac{1.5}{\mathrm{v}}=-\frac{1.5}{0.4} \\ & \mathrm{v}=-0.4 \mathrm{~m}\end{aligned}
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