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JEE Main 202529 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
29 January
Shift
Morning Shift
Subject
Physics
Chapter
Ray Optics

JEE Main 2025 · 29 January · Morning Shift · Physics · Ray Optics

Two light beams fall on a transparent material block at point 1 and...

Two light beams fall on a transparent material block at point 1 and 2 with angle (\theta_1) and (\theta_{2^{\prime}}) respectively, as shown in figure. After refraction, the beams intersect at point 3 which is exactly on the interface at other end of the block. Given : the distance between 1 and 2, (d=\mathrm{d}=4 3 cm\sqrt{3} \mathrm{~cm}) and (\theta_1=\theta_2=\cos ^{-1}\left(\frac{\mathrm{n}_2}{2 \mathrm{n}_1}\right)),whererefractiveindexoftheblock(), where refractive index of the block (\mathrm{n}}_{2}\gt) refractive index of the outside medium (\mathrm{n}}_{1}), then the thickness of the block is ________ cm. Two light beams fall on a transparent material block at point 1 and 2 with angle (θ_1) and (θ_ 2^ ) respectively, as

Correct answer

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Step-by-step solution

Two light beams fall on a transparent material block at point 1 and 2 with angle (θ_1) and (θ_ 2^ ) respectively, as
n1×n22n1=n2sin⁡rsin⁡r=12\begin{aligned} & n_1 \times \frac{n_2}{2 n_1}=n_2 \sin r \\ & \sin r=\frac{1}{2}\end{aligned}r=30∘tan⁡r=(d/2t)t=d2tan⁡r=d32=(43)32=6 cm\begin{aligned} & r=30^{\circ} \\ & \tan r=\left(\frac{d / 2}{t}\right) \\ & t=\frac{d}{2 \tan r}=\frac{d \sqrt{3}}{2}=\frac{(4 \sqrt{3}) \sqrt{3}}{2} \\ & =6 \mathrm{~cm}\end{aligned}$
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