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JEE Main 202522 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Morning Shift
Subject
Physics
Chapter
Ray Optics

JEE Main 2025 · 22 January · Morning Shift · Physics · Ray Optics

Given is a thin convex lens of glass (refractive index μ ) and each...

Given is a thin convex lens of glass (refractive index μ\mu ) and each side having radius of curvature RR. One side is polished for complete reflection. At what distance from the lens, an object be placed on the optic axis so that the image gets formed on the object itself ?

Options

  1. AR/μ\mathrm{R} / \mu
  2. BR/(2μ−3)R /(2 \mu-3)
  3. CμR\mu R
  4. DR/(2μ−1)\mathrm{R} /(2 \mu-1)

Correct answer

D. R/(2μ−1)\mathrm{R} /(2 \mu-1)

Step-by-step solution

−1feq=2fl−1fm=2(μ−1)2R+2R−1feq=2(2μ−1)Rfeq=−R2(2μ−1)\begin{aligned} -\frac{1}{f_{e q}} & =\frac{2}{f_l}-\frac{1}{f_m} \\ & =2(\mu-1) \frac{2}{R}+\frac{2}{R} \\ -\frac{1}{f_{e q}} & =\frac{2(2 \mu-1)}{R} \\ f_{e q} & =-\frac{R}{2(2 \mu-1)} \end{aligned} For concave mirror, object should be at 2f2 f for the image to be at same point  Distance =R(2μ−1)\text{ Distance }=\frac{R}{(2 \mu-1)}
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