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In finding out refractive index of glass slab the following observations were made through travelling microscope 50 vernier scale division =49 MSD ; 20 divisions on main scale in each cm For mark on paper MSR =8.45 ~cm , VC =26 For mark on paper seen through slab MSR =7.12 ~cm , V C=41 For powder particle on the top surface of the glass slab MSR =4.05 ~cm , VC =1 (MSR = Main Scale Reading, VC = Vernier Coincidence) R

Options

  1. A1.52
  2. B1.35
  3. C1.42
  4. D1.24

Correct answer

C. 1.42

Step-by-step solution

aligned & 1 MSD = 1 ~cm 20 =0.05 ~cm & 1 VSD = 49 50 MSD = 49 50 0.05 ~cm =0.049 ~cm & LC =1 MSD -1 VSD =0.001 ~cm aligned For mark on paper, L ₁=8.45 ~cm +26 0.001 ~cm =84.76 ~mm For mark on paper through slab, L 2=7.12 ~cm +41 0.001 ~cm =71.61 ~mm For powder particle on top surface, ZE =4.05 ~cm +1 0.001 ~cm =40.51 ~mm aligned & actual L ₁=84.76-40.51=44.25 ~mm & actual L ₂=71.61-40.51=31.10 ~mm & ~L ₂= L ₁ & = L ₁ ~L ₂ = 44.25 31.10 =1.42 aligned

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