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Two transparent media having refractive indices 1 . 0 and 1 . 5 are separated by a spherical refracting surface of radius of curvature 30   cm . The centre of curvature of surface is towards denser medium and a point object is placed on the principal axis in rarer medium at a distance of 15   cm from the pole of the surface. The distance of image from the pole of the surface is cm .

Correct answer

30

Step-by-step solution

Let's consider the following diagram- The relation between the object distance, the image distance and the radius of curvature of the spherical surface can be written as μ 2 v - μ 1 u = μ 2 - μ 1 R       . . . 1 Substitute the values of the known parameters into equation (1) and solve to calculate the required image distance. 1 . 5 v - 1 - 15 = 1 . 5 - 1 . 0 30 ⇒ 1 . 5 v = 1 60 - 1 15 = - 1 20 ⇒ v = - 30 Hence, the image is formed at a distance of 30   cm from

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